In new and extends clauses, linearization matters. So it’s new A with B {} and that object might have a different implementation than new B with A {}. However, both objects are instances of type A & B.
So with will stay for those? We might want to clarify the documentation, which says
“for the moment, A with B is still allowed, but it will be deprecated and removed in the future”
Yes, with will stay for those. I’ll clarify the docs.
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